(.04225*x^2)+(.1204*x)-1=0

Solution for (.04225*x^2)+(.1204*x)-1=0 equation:

(.04225x^2)+(.1204x)-1=0

We add all the numbers together, and all the variables

(.04225x^2)+(+.1204x)-1=0

We get rid of parentheses

.04225x^2+.1204x-1=0

a = .04225; b = .1204; c = -1;
Δ = b2-4ac
Δ = .12042-4·.04225·(-1)
Δ = 0.18349616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.1204)-\sqrt{0.18349616}}{2*.04225}=\frac{-0.1204-\sqrt{0.18349616}}{0.0845}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.1204)+\sqrt{0.18349616}}{2*.04225}=\frac{-0.1204+\sqrt{0.18349616}}{0.0845}
$